Array of pointer to string

 //in string %s we are writing names without pointer * because %s give value at funtion

#include <stdio.h>


int main()

{

    char *p = "rohit parmar";

    char *q = "vishal parmar";

    

    char *names[] = {

        p,

        q

    };

    printf("%s\n %s\n " , names[0] , names[1]);


    return 0;

}

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