Pointer conversion : pointer casting

 #include <stdio.h>


int main()

{int x = 10;

char c = 'A';

int *p;

char *q;

void *v;

p= (int *)&x;

q=(char *)&c;


    printf("p = %d\n", *p);

    printf ("q= %c\n" , *q);


    return 0;

}

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